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@ -6,14 +6,15 @@ import cn.iocoder.yudao.framework.mybatis.core.mapper.BaseMapperX;
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import cn.iocoder.yudao.framework.mybatis.core.query.LambdaQueryWrapperX;
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import cn.iocoder.yudao.module.promotion.controller.admin.bargain.vo.activity.BargainActivityPageReqVO;
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import cn.iocoder.yudao.module.promotion.dal.dataobject.bargain.BargainActivityDO;
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import com.baomidou.mybatisplus.core.conditions.query.QueryWrapper;
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import com.baomidou.mybatisplus.core.conditions.update.LambdaUpdateWrapper;
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import org.apache.ibatis.annotations.Mapper;
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import org.apache.ibatis.annotations.Param;
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import org.apache.ibatis.annotations.Select;
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import java.time.LocalDateTime;
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import java.util.Collection;
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import java.util.List;
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import java.util.Map;
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/**
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* 砍价活动 Mapper
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@ -86,30 +87,25 @@ public interface BargainActivityMapper extends BaseMapperX<BargainActivityDO> {
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.last("LIMIT " + count));
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}
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// TODO @puhui999：一个商品，在统一时间，不会参与多个活动；so 是不是不用 inner join 哈？
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// PS：如果可以参与多个，其实可以这样写 select * from promotion_bargain_activity group by spu_id ORDER BY create_time DESC；通过 group 来过滤
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/**
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* 获取指定 spu 编号最近参加的活动，每个 spuId 只返回一条记录
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* 查询出指定 spuId 的 spu 参加的活动最接近现在的一条记录。多个的话，一个 spuId 对应一个最近的活动编号
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*
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* @param spuIds spu 编号
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* @param status 状态
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* @return 砍价活动列表
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* @return 包含 spuId 和 activityId 的 map 对象列表
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*/
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@Select("<script> " + "SELECT p1.* " +
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"FROM promotion_bargain_activity p1 " +
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"INNER JOIN ( " +
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" SELECT spu_id, MAX(DISTINCT create_time) AS max_create_time " +
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" FROM promotion_bargain_activity " +
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" WHERE spu_id IN " +
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"<foreach collection='spuIds' item='spuId' open='(' separator=',' close=')'>" +
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" #{spuId}" +
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"</foreach>" +
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" GROUP BY spu_id " +
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") p2 " +
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"ON p1.spu_id = p2.spu_id AND p1.create_time = p2.max_create_time AND p1.status = #{status} " +
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"ORDER BY p1.create_time DESC;" +
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" </script>")
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List<BargainActivityDO> selectListBySpuIdsAndStatus(@Param("spuIds") Collection<Long> spuIds, @Param("status") Integer status);
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default List<Map<String, Object>> selectSpuIdAndActivityIdMapsBySpuIdsAndStatus(@Param("spuIds") Collection<Long> spuIds, @Param("status") Integer status) {
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return selectMaps(new QueryWrapper<BargainActivityDO>()
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.select("spu_id AS spuId, MAX(DISTINCT(id)) AS activityId") // 时间越大 id 也越大 直接用 id
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.in("spu_id", spuIds)
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.eq("status", status)
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.groupBy("spu_id"));
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}
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default List<BargainActivityDO> selectListByIds(Collection<Long> ids) {
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return selectList(new LambdaQueryWrapperX<BargainActivityDO>()
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.in(BargainActivityDO::getId, ids)
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.orderByDesc(BargainActivityDO::getCreateTime));
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}
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}
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puhui999
2 years ago